cusp::sqrt_functor< T > Struct Template Reference

#include <functional.h>

Public Methods
_CCCL_HOST_DEVICE T	operator() (const T &x) const
	Return the square root of x.

Detailed description

template<typename T>
struct cusp::sqrt_functor< T >

sqrt_functor is a function object that computes the square root of a given element.

Parameters

T	is a model of Assignable, and if x is an object of type T, then x=c must be defined and must have a return type that is convertible to T.

Overview

sqrt_functor is a function object. Specifically, it is an Adaptable Unary Function. If f(c) is an object of class sqrt_functor<T>, and x is an object of class T, then f(x) returns sqrt(x).

Example

#include <cusp/array1d.h>
#include <cusp/functional.h>
#include <cusp/print.h>
 
int main()
{
   // create an array with 5 entries from 0 to 4
   cusp::counting_array<float> count(5);
 
   // allocate size of transformed output array
   cusp::array1d<float,cusp::host_memory> v(5, 0);
 
   // compute output vector as transform of tens
   thrust::transform(count.begin(), count.end(), v.begin(), cusp::sqrt_functor<float>());
 
   // v = [0.0, 1.0, sqrt(2), sqrt(3), 2.0]
   cusp::print(v);
}

Definition at line 530 of file functional.h.

Member Function Documentation

operator()()

template<typename T >

_CCCL_HOST_DEVICE T cusp::sqrt_functor< T >::operator() ( const T &  x ) const

inline

Return the square root of x.

Definition at line 534 of file functional.h.